Question

find three consecutive even number such that the sum of twice the least number and thrice the greatest number is 622

Answer 1

Hello mate

Here is your answer,

Let the three consecutive even numbers be x, x+2, x+4.

2(x) + 3(x+4) = 622

2x  + 3x + 12 = 622

5x + 12 = 622

5x = 622 - 12

x = 610/5

x = 122

x+2 = 124

x+4 = 126

Answer 2

let three consecutive even numbers be a-2,a,a+2

given 2(a-2) +3(a+2)=622
2a-4 +3a+6=622
5a+2 =622
a=124
So three consecutive numbers =122,124,126