Question

Find three consecutive even numbers such that the sum of the first and the last numbers
ceeds the second number by 10.
3 mari
8.10, 12
(b) 5,6,7
(c) 8, 10, 13
(d) 7, 10, 1
How many kilo often worth Rs 300 ner should be mixed with 10 kg of tea worth R​

Answer 1

Answer:

The three consecutive numbers are 8,10 and 12.

Step-by-step explanation:

Let the three consecutive even numbers be X , X+2 and X+4

As per the given statement

X + X+4 =X+2 + 10

2X +4 = X + 12

X = 8

So first number is 8

Second number = X+2 = 8 +2 = 10

Third number = X + 4= 8+4 = 12

Answer 2

Step-by-step explanation:

Let x kg of tea worth Rs.300 be added,

Quantity of tea taken that was worth Rs.240 =10 kg

Total quantity of tea that will be produced after mix= (10+x) kg

From the above data, the required equation can be formed as,

300 x + 240 \times 10 = 260(x + 10)300x+240×10=260(x+10)

Solving the above, we get x=5.

Ans:- 5kg of tea worth Rs.300 would serve the purpose.

Hope this answers your question!