Question

find three consecutive natural no.s such that first and the second is 15 more than the third

Answer 1

let the three consecutive natural. no.s be x,x+1 &x+2

By the given condition,

(x) + (x+1) = (x+2) + 15

x + x + 1 = x + 2 + 15

2x + 1 = x + 17

2x - x = 17 - 1

x = 16

So,
The three consecutive natural />no.s:
x = 16
x + 1 = 16 + 1 =17
x + 2 =16 + 2 =18

Therefore,
The three consecutive natural no.s are 16,17 &18.

hope this helps ! ! !