Find three consecutive natural numbers such that the sum of and second is 15 more than the third
Answers
Answered by
1
Answer:
16,17,18
Step-by-step explanation:
Required three consecutive natural numbers are 16,17 and 18
Step-by-step explanation:
Let x,(x+1),(x+2) are three consecutive natural numbers.
According to question
The sum of the first and second is 15 more than the third number.
=> x+(x+1)-(x+2)=15
=> x+x+1-x-2=15
=> x-1=15
=> x = 15+1
=> x = 16
Then
Required three consecutive natural numbers are :
x = 16,
x+1 = 16+1 = 17,
x+2 = 16+2=18
Hope it helps you
Answered by
0
Answer:
let the numbers are (x-1),X,(X+1)
x-1+X=X+1+15
X=17
therefore the numbers are 16,17 ,18
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