Math, asked by neev19, 1 year ago

Find three consecutive natural numbers such that the sum of and second is 15 more than the third

Answers

Answered by Anonymous
1

Answer:

16,17,18

Step-by-step explanation:

Required three consecutive natural numbers are 16,17 and 18

Step-by-step explanation:

Let x,(x+1),(x+2) are three consecutive natural numbers.

According to question

The sum of the first and second is 15 more than the third number.

=> x+(x+1)-(x+2)=15

=> x+x+1-x-2=15

=> x-1=15

=> x = 15+1

=> x = 16

Then

Required three consecutive natural numbers are :

x = 16,

x+1 = 16+1 = 17,

x+2 = 16+2=18

Hope it helps you

Answered by Anonymous
0

Answer:

let the numbers are (x-1),X,(X+1)

x-1+X=X+1+15

X=17

therefore the numbers are 16,17 ,18

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