Find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
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2
Let the no. be x and x+1
x+x+1=39
2x=39-1
2x=38
x=19
•°•Three consecutive no. are 19,20 and 21
|•Thanks•|
x+x+1=39
2x=39-1
2x=38
x=19
•°•Three consecutive no. are 19,20 and 21
|•Thanks•|
Answered by
1
Let the three numbers be: x-1, x and x+1.
-Therefore, x-1 + x + x+1 =3x = 39
-Hence x, the middle number is 13.
-The other two numbers are 12 and 14.:
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