Find three consecutive numbers such that the sum of the second and the third number exceeds the first by 14
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The three consecutive numbers such that
the sum of the second and the third numbers
exceeds the first by 14:
Let the numbers be (x - 1), x and (x + 1).
2x + 1 = (x - 1) + 14
x = 12
The three consecutive integers are 11, 12, and 13.
the sum of the second and the third numbers
exceeds the first by 14:
Let the numbers be (x - 1), x and (x + 1).
2x + 1 = (x - 1) + 14
x = 12
The three consecutive integers are 11, 12, and 13.
richa311:
thanks so much
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