find three consecutive numbers whose sum is 36........ans is 11,12,13 how explain
Answers
Answered by
1
To make the solution easier,
Let three consecutive numbers be ,
(x-1) , x, (x+1),
Now according to the question,
Their sum = 36,
=> x-1 + x + x+1 = 36,
=> 3x = 36,
=> x = 12 ( middle of three numbers ),
Now first number is x - 1 = 12-1 = 11,
Third number is x +1 = 12+1 = 13,
Therefore the three numbers are,
11, 12, 13,
Hope you understand,
Have a great day !!
Let three consecutive numbers be ,
(x-1) , x, (x+1),
Now according to the question,
Their sum = 36,
=> x-1 + x + x+1 = 36,
=> 3x = 36,
=> x = 12 ( middle of three numbers ),
Now first number is x - 1 = 12-1 = 11,
Third number is x +1 = 12+1 = 13,
Therefore the three numbers are,
11, 12, 13,
Hope you understand,
Have a great day !!
Answered by
0
let the smaller number be x
so other two are x+1, x+2
by the given condition
x+x+1+x+2=36
3x+3=36
3x=33
x=11
x+1=11+1=12
x+2=11+2=13
so the number are 11, 12&13
so other two are x+1, x+2
by the given condition
x+x+1+x+2=36
3x+3=36
3x=33
x=11
x+1=11+1=12
x+2=11+2=13
so the number are 11, 12&13
Similar questions