Question

find three consecutive numbers whose sum is is 108.[Hint. Let the consectutive number be x,x+1,x+2.1]​

Answer 1

Answer:

35+36+37 = 108

Step-by-step explanation:

Let the consectutive number be x,x+1,x+2

So, x+(x+1)+(x+2) = 108

3x+3 =108

3x= 105

x = 35

So, the first number x = 35

second number (x+1) = 35+1 = 36

Third number (x+2) = 35+2 = 37

Answer 2

$\huge\red{\boxed{\sf ANsWEr}}$

Let three consecutive integers be :

x,x+1 and x+2

According to question,

→x+(x+1)+(x+2)=108

→3x+3=108

→3x=105

→x=35

Required numbers are,

x=35,x+1=36 and x+2=37

Hence Numbers are

$\huge\purple{\boxed{\sf 35,36,37}}$