Question

find three consecutive odd natural numbers such that the sum of the first and the second is 15 more than the third​

Answer 1

Solution :-

Let the three consecutive natural numbers are

x+ 1 , x + 3 , x + 5 .

Here, The sum of first and second consecutive odd number

= 15 + 3rd odd number .

Therefore , According to the question .

( x + 1 ) + ( x + 3 ) = 15 + ( x + 5)

x + 1 + x + 3 = 15 + x + 5

2x + 4 = 20 + x

2x - x = 20 - 4

x = 16

Hence , The value of x is 16

Therefore ,

Three consecutive odd natural numbers are ,

x + 1 = 16 + 1 = 17

x + 3 = 16 + 3 = 19

x + 5 = 16 + 5 = 21

• Odd numbers are those numbers which when divided by 2 leaves remainder 1 .

• Consecutive numbers are defined as nbers that arrange in continous form from smaller to larger .

Answer 2

$\sf \bold{solution}$

let 3 consecutive odd natural numbers be

x-1, x+1, x+3

Given, sum of first and second consecutive odd number is 15 more than third number

i.e (x-1)+(x+1) = 15+(x+3)

2x= 18+x

x= 18

So, the three odd natural consecutive numbers are :

• x - 1 = 18 - 1 = 17
• x + 1 = 18 + 1 = 19
• x + 3 = 18 + 3 = 21