Question

find three consecutive odd number whose sum is 447

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Answer 1

${\blue{\huge{\text{Answer}}}}$

Given;-

• 3 is consecutive numbers
• Their sum is 447

To find:-

• The 3 numbers

Let

• The 3 numbers are x,(x+2),(x+4)

Now,

According to the question

x+(x+2)+(x+4)=447

x+x+2+x+4=447

3x+6=447

3x=447-6

3x=441

x=$\frac{441}{3}$

x=147

So, the numbers are

• 147
• 147+2=148
• 147+4=151

Verification:-

147+148+151=447

Hope it helps

Answer 2

Given :

• Sum of three consecutive numbers = 447

To Find :

The three consecutive odd numbers.

Solution :

Let the First number be x , second number be (x + 2) and third number be (x + 4).

So , according to the Question , we get the Equation as :-

$\underline{\boxed{:\implies \bf{a + b + c = 447}}}$

Where :-

• a = First number
• b = Second number
• c = Third number

Now , putting the value of three numbers (in terms of x) , we get :-

$\underline{:\implies \bf{x + (x + 2) + (x + 4) = 447}}$

$:\implies \bf{x + (x + 2) + (x + 4) = 447}$

$:\implies \bf{3x + 6 = 447}$

$:\implies \bf{3x = 447 - 6}$

$:\implies \bf{3x = 441}$

$:\implies \bf{x = \dfrac{441}{3}}$

$:\implies \bf{x = 147}$

Hence, the value of x is 147.

Now ,by putting the value of x in the values of three consecutive numbers (in terms of x) , we get :-

First Number :-

$:\implies \bf{x}$

$:\implies \bf{147}$

Hence, the first number is 147.

Second Number :-

$:\implies \bf{x + 2}$

$:\implies \bf{147 + 2}$

$:\implies \bf{149}$

Hence, the second number is 149.

Third Number :-

$:\implies \bf{x + 4}$

$:\implies \bf{147 + 4}$

$:\implies \bf{151}$

Hence, the third number is 151.

Hence, the three consecutive odd numbers are 147 , 149 and 151.