Find y, if y= x² sinx use leibnitz
Answers
Answered by
0
Answer:
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Answered by
0
Answer:
y=x
2
sinx
Using
dx
d(u .v)
=v
dx
du
+u
dx
dv
Differentiating on both sides
⟹
dx
dy
=
dx
d
(x
2
sinx)
⟹
dx
dy
=sinx
dx
d
(x
2
)+x
2
dx
d
(sinx)
⟹
dx
dy
=2xsinx+x
2
cosx
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