Question

Find y, if y= x² sinx use leibnitz
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Answer 1

Answer:

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Answer 2

Answer:

y=x

2

sinx

Using

dx

d(u .v)

=v

dx

du

+u

dx

dv

Differentiating on both sides

⟹

dx

dy

=

dx

d

(x

2

sinx)

⟹

dx

dy

=sinx

dx

d

(x

2

)+x

2

dx

d

(sinx)

⟹

dx

dy

=2xsinx+x

2

cosx