Question

find three consecutive position even

intergers whose sum is 90

Answer 1

Heya Mate!!

Here is your solution!!

Answer!!

Let the positive even numbers be n, n+2, n+4

Given that n+n+2+n+4=90

3n+6=90

3n=84

n= 28

Therefore the numbers are 28, 30, 32.

__________@Rajasthani

Answer 2

Answer:

Step-by-step explanation:

First be x

Second be x+1

third be x+2

acc to que

x+x+1+x+2=90

3x+3=90

3x=87

x=87/3

x= 29

So

First be 29

Second be 30

thief be 31

Hope its helps u ✌✌✌