Question

Find three consecutive positive integer such that the sum of the first integer and the product of the other two is 92

Answer 1

Let the 3 integers be ×,×+1 &×+2.

Now, (x+1)(x+2)= x^2+3x+2

:. x^2+3x+2+x=92

:. x^2+4x-90=0

solve this quadratic equation to get value of x.

Answer 2

Here's ur answer ,

Let the positive integer be x ,

Let The three positive integers be x ,x+1, x+2

By the given condition ,

x +(x+1×x+2) =92
x+(x+1x+2) =92
x+(x+x+2)= 92
x+(2x+2)=92
x+2x+2=92
x+2x=92-2
3x =90
x=90÷3
x=30

The three consecutive positive integers will be
x=30
x+1=31
x+2=32

Hence the three consecutive terms are 30 ,31 and 32

Hopeit helps you!