Question

Find three numbers in AP whose sum is 6 and product is 6 respectively

Answer 1

Answer:

Step-by-step explanation:

Let the three numbers be

a-d,a,a+d

Sum of numbers=6

a-d+a+a+d=6

a+a+a=6

3a=6

a=2

Product of numbers=6

a-d×a×a+d=6

a-d×a+d×a=6

[a-b×a+b=a^2-b^2]

a^2-d^2×a=6

Substitute the value of a

2^2-d^2×2=6

4-d^2=6/2

4-d^2=3

-d^2=3-4

-d^2=-1

d^2=1

d=root over 1

d=+ or - 1

Therefore A.P will be

a=2 d=1

2,3,4,5,6...........

Or

a=2 d=-1

2,1,0,-1,-2..........

Answer 2

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