Question

find three numbers in the ratio 2:3:5 and sum of the squares is 608​

Answer 1

Answer:

Step-by-step explanation:

Let the common multiple be x. Therefore the numbers are 2x,3x and 5x

Now (2x)²+(3x)²+(5x)²=608

4x²+9x²+25x²=608

38x²=608

x²=608/38=16

Therefore x=+4 or -4

Therefore the numbers are 2(4),3(4),5(4)

8,12,20

or -8,-12,-20