Question

Find three odd consecutive numbers whose sum is 33.

Answer 1

Step-by-step explanation:

Let the 3 numbers be x,x+2,x+4

According to Question

(x)+(x+2)+(x+4)=33

x+x+2+x+4=33

3x+6=33

3x=27

x=27/3

x=9

Therefore the three odd consecutive numbers whose sum is 33 are

9,11,13

Answer 2

Answer:

Let the three odd consecutive numbers be x+1, x+3 and x+5.

Sum = 33.

Sol;

x+1+x+3+x+5 = 33

=> 3x+9 = 33

=> 3x = 33-9

=> x = 24/3

=> x = 8

1st odd Consecutive number = x+1 = 8+1 = 9.

2nd odd Consecutive number = 8+3 = 11.

3rd odd Consecutive number = 8+5 = 13.