Find tn for Arithmetic Progression where t3=22,t17= -20
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As we know,
tn = a+(n-1)d
Now t3 = 22 and t17 = -20
so, t3 = a+(3-1)d
= a+2d ......eq(1)
similarly , t17 = a+16d ......eq(2)
Now solving eq(1) and eq (2) by elimination method...
we get d = -3 and a = 28
so tn = 28+(n-1)(-3)
tn = a+(n-1)d
Now t3 = 22 and t17 = -20
so, t3 = a+(3-1)d
= a+2d ......eq(1)
similarly , t17 = a+16d ......eq(2)
Now solving eq(1) and eq (2) by elimination method...
we get d = -3 and a = 28
so tn = 28+(n-1)(-3)
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