Question

Find trigonometric ratio of 0 degree geometrically

Answer 1

Answer:

sin 0° = √(0/4) = 0sin 30° = √(1/4) = ½sin 45° = √(2/4) = 1/√2 = √2/2sin 60° = √3/4 = √3/2;cos 90° = √(4/4) = 1. sec 0° = 1sec 30° = 2√3/3sec 45° = √2sec 60° = 2sec 90° = not defined. csc 0° = not defined. csc 30° = 2csc 45° = √2csc 60° = 2√3/3csc 90° = 1

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