find two consecutive odd integers such that two fifth of the smaller exceeds two ninth of the greater by 4
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let 1st consecutive be X
and 2nd be X+2
A/Q
2X/5-2(X+2)/9=4
2(X/5-X+2/9)=4
9X-5X-10/45=2
4X-10/45=2
4X-10=90
4X=100
X=25
1st no=25
2nd no 27
and 2nd be X+2
A/Q
2X/5-2(X+2)/9=4
2(X/5-X+2/9)=4
9X-5X-10/45=2
4X-10/45=2
4X-10=90
4X=100
X=25
1st no=25
2nd no 27
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