find two consecutive odd whole numbers whose product is 63
Lawliet:
7 and 9
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Answered by
12
7 and 9
We got that answer by,
Let one number is x, other will be x+2
∴x(x+2)=63
x²+2x=63
x²+2x-63=0
x²+9x-7x-63=0
x(x+9)-7(x+9)=0
∴ x=7
and first number is 7 and 2nd number is x+2=7+2=9
We got that answer by,
Let one number is x, other will be x+2
∴x(x+2)=63
x²+2x=63
x²+2x-63=0
x²+9x-7x-63=0
x(x+9)-7(x+9)=0
∴ x=7
and first number is 7 and 2nd number is x+2=7+2=9
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Answered by
2
By prime factorization
63=3×3×7
63=9×7
here 7&9are consecutive odd numbers.Hence the required two numbers are "7" and "9".
63=3×3×7
63=9×7
here 7&9are consecutive odd numbers.Hence the required two numbers are "7" and "9".
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