Question

find two consecutive positive even integer whose product is224​

Answer 1

Answer:

14 and 16

Step-by-step explanation:

Let the first integer is x,

the next integer = x + 2

Product = x*(x+2) = x²+2x = 224

x² + 2x - 224 = 0

(x-14)(x+16)=0

x = 14 or -16

ignoring the negative value,

x = 14

x+2 = 14+2 = 16

The numbers are 14 and 16

Answer 2

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Integers Be Let the two Consecutive Positive Even :

• First No. = x
• Second No. = (x + 2)

A.T.Q

➟ (x) × (x + 2) = 224

➟ x² + 2x = 224

➟ x² + 2x - 224 = 0

➟ x² + 16x - 14x - 224 = 0

➟ x(x + 16) - 14(x + 16) = 0

➟ (x + 16)(x - 14) = 0

➟ (x + 16) = 0⠀⠀⠀ or, ⠀⠀⠀(x - 14) = 0

➟ x = -16 ⠀⠀or,⠀⠀x = 14

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★ As We Are Talking about Positive Integers ; So we Will Take x = 14

• First No. = x = 14
• Second No. = (x + 2) = (14 + 2) = 16

$\huge{\red{\ddot{\smile}}}$