Question

Find two numbers such that one of the number exceeds The Other by 7 and their sum is 69​

Answer 1

let one number be x

other no x+7

sum of both=x+x+7=2x+7=69
x=62÷2=31
x+7=31+7=38

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Answer 2

Let one of the number be x .

Let the other number be y .

Now we are given that the other number exceeds one number by 7 .

Hence we can write that y = x + 7 since y exceeds x by 7 .

NOTE :

When a number exceeds , it has to be greater than the number .

y > x .

Now their sum is given 69 .

So adding x and y gives 69 .

x + y = 69.

Putting the substituted value of y we get :

⇒ x + x + 7 = 69

⇒ 2 x + 7 = 69

⇒ 2 x = 69 - 7

⇒ 2 x = 62

⇒ x = 62/2

⇒ x = 31

So we note that the numbers are x and y .

y = x + 7

⇒ y = 31 + 7

⇒ y = 38 .

Hence the two numbers are 38 and 31 .