find two numbers such that one of them exceeds the other by 18 and other sum is 92
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Hi ,
Let x , ( x + 18 ) are the numbers
Their sum = 92
x + x + 18 = 92
2x = 92 - 18
2x = 74
x = 74/2
x = 37
Therefore ,
Required numbers are ,
x = 37 ,
x + 18 = 37 + 18 = 55
I hope this helps you.
:)
Let x , ( x + 18 ) are the numbers
Their sum = 92
x + x + 18 = 92
2x = 92 - 18
2x = 74
x = 74/2
x = 37
Therefore ,
Required numbers are ,
x = 37 ,
x + 18 = 37 + 18 = 55
I hope this helps you.
:)
math83:
this answer correct but how u solve this
here i took a number = x
another number which exceeds first number by 18 means , 18 more than x
second number = x + 18
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