Find two numbers such that one of them exceeds the other by 9 and their sum is 81.
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Given :
- Two numbers such that one of them exceeds the other by 9 and their sum is 81.
To Find :
- The Two Numbers
Solution :
⟶ Let the First number be x
⟶ Then Second number will be x + 9
According to the Question :
⟹ Sum of Numbers = 81
⟹ x + x + 9 = 81
⟹ 2x + 9 = 81
⟹ 2x = 81 - 9
⟹ 2x = 72
⟹ x = 72/2
⟹ x = 36
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Verification :
⟹ Sum of Numbers = 81
⟹ x + x + 9 = 81
⟹ 36 + 36 + 9 = 81
⟹ 36 + 45 = 81
⟹ 81 = 81
Hence Verified
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Therefore :
- First Number = x = 36
- Second Number = x + 9 = 36 + 9 = 45
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