find two numbers such that one of them is five times the other and their difference is 132
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Let the first number be x and the another be y.
Then x - y =132 ....(1)
Also, x= 5y or x -5y = 0 ...(2)
On doing (1) - (2),
We get
= 4y = 132
y = 33
x = 5y
x = 5 ×33
x = 165.
Therefore, the two numbers are 165 and 33.
Then x - y =132 ....(1)
Also, x= 5y or x -5y = 0 ...(2)
On doing (1) - (2),
We get
= 4y = 132
y = 33
x = 5y
x = 5 ×33
x = 165.
Therefore, the two numbers are 165 and 33.
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