Question

Find two numbers such that the sum of twice the first and thrice the second is 89 and four times the first exceeds five times the second by 13​

Answer 1

Answer:

Here's your answer mate

Step-by-step explanation:

Let the two numbers be x and y.

Then, equation formed are 2x + 3y = 89 ....(i)

4x - 5y = 13 ...(ii)

On solving eq. (i) & (ii) we get

x = 22

y = 15

Hence required numbers are 22 & 15.

Hope it helps you

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