Question

Find two numbers whose difference is 13 and product is 48.​

Answer 1

Answer:

✅Here's your answer

#Let the numbers be x and 13+x...

#ACCORDING TO THE QUESTION...

#(x+13) x=48

${x}^{2} + 13x - 48 = 0 \\ \\ {x}^{2} + 16x - 3x - 48 = 0 \\ \\ x(x + 16) - 3(x + 16) = 0 \\ \\ (x + 16)(x - 3) = 0 \\ \\ x = - 16 \: and \: 3$

#Number cannot be in negative... So the required number is 3...

#the Numbers are 3 and 16...

Hope it helps ✌