find two solutions for equations 4x +3y = 12
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Answered by
8
x = 0
3y=12 y = 4
x =0, y =4
y=0
4x=12. x=3
x=3, y=0
3y=12 y = 4
x =0, y =4
y=0
4x=12. x=3
x=3, y=0
abhijith12367:
thank you for the answer
Answered by
2
Answer:
4x+3y=12
4x=12-3y
put 4x=12-3y then 12-3y+3y=12, then 12=12 the answer 0
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