Question

find two solutions for the equation 4x+3y=12

Answer 1

Answer:

Given equation is 4x+3y =12

case 1. When X = 0 we get

3y = 12

therefore y = 4

then (0,4) is the first solution.

and case.2 When Y =0

we get 4x = 12

therefore x = 3

therefore  (0, 3) is the second solution

Hence (0,4) and (0, 3) are the two solution.

Answer 2

Answer:

4(0) +3y =12 ⇒ 3y =12. ⇒ y = 12 / 3 = 4. So, (0, 4) is a solution of given equation. ...

4(1) + 3y=12 ⇒ 3y = 12 - 4 = 8 ⇒ y = 8 / 3. So, (1,8 / 3) is another solution of the given equation. ...

4(2) + 3y = 12 ⇒ 3y = 12 - 8 = 4 ⇒ y = 4 / 3. So, (2, 4 / 3) is also a solution of the given equation