Question

α-β find value in equation ax2 + bx + c =0

Answer 1

ax²+bc+c = 0
A and ß are zeroes of the equation

We know that,

A+ß = -b/a
Aß = c/a

(A-ß)² = (A+ß)² - 4Aß
(A-ß)² = (-b/a)² - 4(c/a)
(A-ß)² = b²/a² - 4c/a
(A-ß)² = (b²-4ac)/a²
(A-ß) = √(b²-4ac)/a²
A-ß = [√(b²-4ac)]/a

Hope it helps