Question

find value of B. B + ( B/4 ) * 7 + [( B*2) - ( B-2 ) (B-2)] +5 - (B*B) = B​

Answer 1

Answer:

Step-by-step explanation:

B+(B/4)*7+[(B*2)-(B-2)(B-2)]+5-(B*B)=B

(B/4)*7+[(B*2)-(B-2)(B-2)]+5-(B*B)=B-B

7B/4+2B-B²-4+4B+5-B²=0

L.C.M

7B+8B-4B²-16+16B+20-4B²=0/4

-8B²+31B+4=0

-(8B²-31B-4)=0

8B²-31B-4=0

Factorisation:

B-4=0;8B+1=0

B=4; B=-1/8