Find value of tanπ8 in easy way
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we know tht
tan a = 2 tan a/2 / 1 - tan sqyare a/2
putting a = pie/4, we get
tan pie/4 = 2 tan pie/8 / 1 - tan square pie/8
1 = 2 tan pie/8 / 1 - tan square pie/8 ---------------- 1
let tan pie/8 = x, thn frm (1) 2x/ 1 - x square = 1
2x = 1 - x square
x square + 2x - 1 = 0
x = -2 +- underroot 4 + 4/2
x = -2 +- 2 root2/2
x = -1 +- root2
tan a = 2 tan a/2 / 1 - tan sqyare a/2
putting a = pie/4, we get
tan pie/4 = 2 tan pie/8 / 1 - tan square pie/8
1 = 2 tan pie/8 / 1 - tan square pie/8 ---------------- 1
let tan pie/8 = x, thn frm (1) 2x/ 1 - x square = 1
2x = 1 - x square
x square + 2x - 1 = 0
x = -2 +- underroot 4 + 4/2
x = -2 +- 2 root2/2
x = -1 +- root2
Answered by
0
the value of tanπ 8 is -1× -2 cos
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