find value of x in the question
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(8/15)^3-(1/3)^3-(1/5)^3=x/75
[(8/15)-(1/3)-(1/5)]^3=x/75
[(8-5-3)/15]^3=x/75
(0/15)^3=x/75
{(0/15)×75}^3=x
(5)^3=x
125=x
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[(8/15)-(1/3)-(1/5)]^3=x/75
[(8-5-3)/15]^3=x/75
(0/15)^3=x/75
{(0/15)×75}^3=x
(5)^3=x
125=x
HOPE IT WILL HELP U..
PLZ MARK IT AS BRAINLIEST ANSWER..
Anonymous:
hey how did 75 ^3 come in the last step i think it is wrong
Answered by
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(8/15-1/3-1/5)^3=x/75
((8-5-3)/15)^3=x/75
(0/15)^3=x/75
0/225*15=x/75
0/3375=x/75
0/3375*75=x
0*75=x
x+
x=75*0=0
((8-5-3)/15)^3=x/75
(0/15)^3=x/75
0/225*15=x/75
0/3375=x/75
0/3375*75=x
0*75=x
x+
x=75*0=0
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