Math, asked by nana73, 11 months ago

find value
 \sqrt{4}  +  \sqrt{9}  +  \sqrt{36} +  \sqrt{1024}

Answers

Answered by Anonymous
2

Hii its tom85

 \sqrt{4 }  +  \sqrt{9}  +  \sqrt{36}  +  \sqrt{1024}

=2 + 3 +6 + 32

=11 + 32

=43

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hope it may helps you

Answered by Anonymous
5

Answer:

49✔✔

Step-by-step explanation:

 \sqrt{4}  +  \sqrt{9}  +  \sqrt{36}  +  \sqrt{1024}  \\ first \: we \: factorise \: the \: value \: in \: underoot \: so \: we \: can \: get \: pairs \: of \: two \: number \\  \sqrt{2 \times 2}  +  \sqrt{9 \times 9}  +  \sqrt{6 \times 6}  +  \sqrt{32 \times 32}  \\ then \: we \: choose \: common \: in \: all \: the \: roots \\  = 2 + 9 + 6 + 32  \\  = 49

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