Question

Find values of k if area of triangle is 4sq.units and vertices are (−2,0),(0,4),(0,k)

Answer 1

Answer:

k=16

Step-by-step explanation:

area =1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

4=1/2(-8+k)

8=-8+k

thus,k=16