Question

Find √x+1/√x and x² + 1/x² if x= 1 /√3+2
please help! no unnecessary answers please ​

Answer 1

Answer:

Step-by-step explanation:

$x+1/x ?\\x^{2} + 1/x^{2} ?\\x=1/\sqrt{3} +2\\so sollution is :\\x+1/x = 1/\sqrt{3}+2 + \sqrt{3}+2\\ = 1+ (\sqrt{3} +2)^{2} / \sqrt{3}+2\\ = (1+3 + 4 + 4\sqrt{3} )/ \sqrt{3}+2\\ = (8+4\sqrt{3})/\sqrt{3}+2\\taking 4 common\\ = 4(2+\sqrt{3})/\sqrt{3}+2\\ =4 \\\\Now for x^{2} + 2/x^{2} \\x^{2} +1/x^{2} = (x+1/x)^{2} - 2\\ puting value of x + 1/ x\\ = 4 - 2 \\ = 2 \\hence you got the answer$