Question

find x and y in this question

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Answer 1

Answer:

In ∆CED

angle CED +27°+25°=180°

angle CED= 180°-52°=128°

angle CED + x=180°. (LP)

128°+x=180°

x=52°

In ∆ABC

BC II DE and CD is transversal

25°= angle BDC (alt. int. angle)

25°+27°+angle ADE=180°. (LP)

angle ADE=180°-52°=128°

In ∆ADE

angle ADE+x+y=180°

128°+52°+y=180°

y=180°-180°=0

Hope it helps....