Find x if , √(1+x√(x²+24)) = x+1
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Answer:
square both sides
1+x√(x^2+24)=x^2+2x+1
x√(x^2+24)=x^2+2x=x(x+2)
Divide both sides by x (this gives one solution of x=0) again square both sides
x^2+24= x^2+4x+4
4x=20
x=5
So there are two values of x: 0 and 5
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