Find x if in triangle abc a=2x-5 b=x and exterior angle c=115
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4
exterior angle is the sum of opposite interior angles ,
so, 2x-5 +x = 115
= 3x = 120
= x = 40°
so, 2x-5 +x = 115
= 3x = 120
= x = 40°
Answered by
3
in triangle
ext angle = sum of interior opposite angle
c= a+b
115 = 2x-5+x
115 = 3x-5
115+5 = 3x
120=3x
x= 120/3
x= 40
a= 2(40)-5
= 80-5
= 75°
b= x
b= 40°
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ext angle = sum of interior opposite angle
c= a+b
115 = 2x-5+x
115 = 3x-5
115+5 = 3x
120=3x
x= 120/3
x= 40
a= 2(40)-5
= 80-5
= 75°
b= x
b= 40°
HOPE IT HELPS
PLEASE MARK IT AS BRAINLIEST
DON'T FORGET TO FOLLOW
THANKS
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