In , ∆ABC ,if A-B = 33 and B-C= 18°,then angle B = ?
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A-B=33
A=33+B.....(1)
B-C=18
C=B-18.....(2)
A+B+C=180°
33+B+B+B-18=180°
3B+15=180°
3B=165
B=165/3
B=55°...(Ans)
THIS MAY HELP U ...
A-B=33
A=33+B.....(1)
B-C=18
C=B-18.....(2)
A+B+C=180°
33+B+B+B-18=180°
3B+15=180°
3B=165
B=165/3
B=55°...(Ans)
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