find x? it is a integer problem
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you can write x^-3/4 as 1/(x³)^1/4
1/(x³)1/4 = 1/2³ (Given).................................eq1
by comparing we get
x^1/4 = 2
Now quadrupling both sides we get
quadrupling is taking power 4 on both sides like we do at the time of squaring both sides
x = 2^4
x = 16
You can also verify this by putting the value of x=16 in first equation and both RHS = LHS
poojamurugesan:
thank you so much
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you can write x^-3/4 as 1/(x³)^1/4
1/(x³)1/4 = 1/2³ (Given)
by comparing we get
x^1/4 = 2
Now quadrupling both sides we get
quadrupling is taking power 4 on both sides like we do at the time of squaring both sides
x = 2^4
x = 16
You can also verify this by putting the value of x=16 in first equation and both RHS = LHS
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