Question

If a person walks at 4 mph, he covers a certain distance. If he walks at 9 mph, he covers 7.5 miles more. How much distance did he actually cover?

Please help me solve it!
Thanks!

Answer 1

Given:

A certain distance is covered when a person walks at 4 mph. When he walks at 9 mph , he covers 7.5 miles more.

To find:

Actual distance covered by the man.

Calculation:

Let's consider the actual distance covered by the man to be "x" miles.

In 1st Case:

x miles is covered buy the man at a speed of 4 mph in a specified time t. Mathematically , it can be represented as :

$\therefore \: x = speed \times time$

$= > x = 4 \times t$

$= > x = 4t$

In 2nd case:

The man covers an additional distance of 7.5 miles when he moves at a speed of 9 mph in that specified time interval.

$\therefore \: x + 7.5 = speed \times time$

$= > x + 7.5 = 9 \times t$

$= > x + 7.5 = 9 t$

Now , solving the 2 equations , we get :

$= > 4t + 7.5 = 9 t$

$= > 5t = 7.5$

$= > t = 1.5 \: hr$

Putting the value of t in the 1st equation :

$\therefore x = 4t$

$= > x = 4 \times 1.5$

$= > x = 6 \: miles$

So the final answer:

Actual distance covered by man is 6 miles..

Answer 2

Answer:

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