Math, asked by hiab143, 10 months ago

find y in given equation - 7y-1/4-(2y-1-y/2)=10/3​

Answers

Answered by anishkhan01pcqmys
0

Answer:

y = 31/66

Step-by-step explanation:

7y - 1/4 - (2y - 1 - y/2) = 10/3

7y -1/4 - (4y/2 - 2/2 - y/2) =10/3

7y - 1/4 - (3y/2 - 2/2) =10/3

7y -1/4 - 3y/2 + 2/2 = 10/3

7y - 3y/2 - 1/4 + 2/2 = 10/3

28y/4 - 6y/4 - 1/4 + 4/4 = 10/3

22y/4 + 3/4 = 10/3

3( 22y + 3) = 10 x 4 ( cross multiply)

66y + 9 = 40

66y = 40 - 9

66y = 31

y = 31/66

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