Question

Find zeroes for the polynomial 4u^2+8u

Answer 1

p (u) = 4u²+8u
if we put u =1 we get
p (1) = 4x1²+8x1
= 4+8
=12

putting u = 2
we get,
p(2)= 4x2²+8x2
=4x4+16
=16+16
=32

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Answer 2

FULL ANSWER WITH STEPS

We have to find the zeroes or roots of the polynomial $4u^{2}+8u$. 
Now, 
$4u^{2}+8u=0$
⇒ $(u)(4u+8)=0$

Roots of the polynomial: 
1) $u=0$

2) $4u+8=0$
⇒ $4u=-8$
⇒ $u=-2$

∴ The zeroes or roots of the polynomial $4u^{2}+8u$ are $u=0, u=-2$. 

Hope this may help you. 

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