Find zeroes for the polynomial 4u^2+8u
Answers
Answered by
1
p (u) = 4u²+8u
if we put u =1 we get
p (1) = 4x1²+8x1
= 4+8
=12
putting u = 2
we get,
p(2)= 4x2²+8x2
=4x4+16
=16+16
=32
I hope u find this answer helpful
Mark It as brainilist
if we put u =1 we get
p (1) = 4x1²+8x1
= 4+8
=12
putting u = 2
we get,
p(2)= 4x2²+8x2
=4x4+16
=16+16
=32
I hope u find this answer helpful
Mark It as brainilist
Answered by
5
FULL ANSWER WITH STEPS
We have to find the zeroes or roots of the polynomial .
Now,
⇒
Roots of the polynomial:
1)
2)
⇒
⇒
∴ The zeroes or roots of the polynomial are .
Hope this may help you.
If you have any doubt, then you can ask me in the comments.
We have to find the zeroes or roots of the polynomial .
Now,
⇒
Roots of the polynomial:
1)
2)
⇒
⇒
∴ The zeroes or roots of the polynomial are .
Hope this may help you.
If you have any doubt, then you can ask me in the comments.
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