find zeroes of 2x^2-7x
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Hi ,
Let p ( x ) = 2x² - 7x
To find zeroes we have make
p ( x ) = 0
2x² - 7x = 0
x ( 2x - 7 ) = 0
x = 0 or 2x - 7 = 0
x = 0 or x = 7/2
Therefore ,
0 or 7/2 are zeroes of p ( x )
I hope this helps you.
:)
Let p ( x ) = 2x² - 7x
To find zeroes we have make
p ( x ) = 0
2x² - 7x = 0
x ( 2x - 7 ) = 0
x = 0 or 2x - 7 = 0
x = 0 or x = 7/2
Therefore ,
0 or 7/2 are zeroes of p ( x )
I hope this helps you.
:)
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