Question

Find zeroes of p(x) = x^3-5x^2-16x+80 , if two are equal in magnitude but opposite in sign .



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Answer 1

$\huge \mathfrak \green{ÆÑẞWĒR}$

Step-by-step explanation:

since 2 roots are of different sign and same magnitude

$let \: roots \: are \: ± \: α,β$

$α−α+β=5$

$β=5$

$−α2β=80$

$± \: α= \sqrt{16}$

$α=±4$

$roots \: are 4,−4 and 5$

$\blue{i \: hope \: it \: helpfull \: for \: you}$