Question

find zeros of the polynomial 5x^2+6x+1 and verify the relation between zeros and coefficients​

Answer 1

Answer:

0

Step-by-step explanation:

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Answer 2

Answer:

P(x) = 5x^2 + 6x + 1

P(x) = 5x^2 + 5x + x + 1

P(x)= 5x( x+1 ) +1( x+1 )

P(x) = (x+1) ( 5x +1 )

so the factors of P(x) are (x+1) and (5x+1 )

zeros are x= -1

x= -1/5

sum of zeros = -1 +(-1/5) = -6/5

= -( coefficient of x) / coefficient of x^2

product of zeros = -1×-1/5 = 1/5

= constant term / coefficient of x^2

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