fine the value of k if x=3, y=-1 is a solution of 2x+5y=k
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Let x = 3
y = -1
2x+5y = k
2 (3) +5 (-1) = k
6+ (-5) = k
6-5 = k
1 = k
Therefore k = 1
y = -1
2x+5y = k
2 (3) +5 (-1) = k
6+ (-5) = k
6-5 = k
1 = k
Therefore k = 1
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