Question

Five cards−−the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random. (i) What is the probability that the card is the queen? (ii) If the queen is drawn and put aside, what is the probability that the second card picked up is (a) an ace? (b) a queen?

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

According to the question:

Total cards = 5

{ ten, jack, queen, king and ace of diamonds}

(i) What is the probability that the card is the queen?

Answer:

$Probability= \frac{favourable \: outcome}{total \: outcome} \\ \\ P(Q) = \frac{1}{5}$

(ii) If the queen is drawn and put aside, what is the probability that the second card picked up is (a) an ace? (b) a queen?

Answer: Now that queen card put aside,so

Total cards are now: 4

Out of these four cards,Now probability of card to be an ace P(A)

$P(A) = \frac{1}{4}$

Probability of having a queen ,if queen us fetched earlier and put aside P(Q2)

$P(Q2)= \frac{0}{3} \\ \\ P(Q2) = 0$

Since no queen is in the pack.

Hope it helps you.