Math, asked by yashjade2003, 9 months ago

Five forces AB, AC, AD, AE and AF act at the vertex of a regular hexagon ABCOEF. 03
the centre of the hexagon. The resultant of these forces is
b) 5 OA
5 AO
g) 6 AO​

Answers

Answered by rishabkumar7
0

Answer:

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Answered by venkidvenkat54
0

Step-by-step explanation:

AB+AC+AD+AE+AF=AB+(AC+AF)+AO+AE

                                =AB+(AC+CO)+AD+AE   [since AF=CD]

                                =AB+AD+AO+AE

                                =2AD+(AB+AE)

                                =2AD+(ED+AE)               [since  AB=ED]

                                =2AD+AD

                                =3AD

                                =3*(2AO)          [since O is the center and AO=OD]

                                =6AO

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