Five forces AB, AC, AD, AE and AF act at the vertex of a regular hexagon ABCOEF. 03
the centre of the hexagon. The resultant of these forces is
b) 5 OA
5 AO
g) 6 AO
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Answer:
lalu gadhe mere 8th me 87 percent aaye khush khabri 9th me 89 and 10th me 99
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Step-by-step explanation:
AB+AC+AD+AE+AF=AB+(AC+AF)+AO+AE
=AB+(AC+CO)+AD+AE [since AF=CD]
=AB+AD+AO+AE
=2AD+(AB+AE)
=2AD+(ED+AE) [since AB=ED]
=2AD+AD
=3AD
=3*(2AO) [since O is the center and AO=OD]
=6AO
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